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a bullet that is shot from a target is travelling at an initial speed of 80 m/s and it is 6 m away from its target. The target is wearing a bullet proof vest that is 0.26 m thick. As the bullet makes contact with the vest is slows down at a rate of 9000 m/s2. What is the final velocity of the equation?

I would assume that the equation used would be Vf^(2) = Vi^(2) + 2ad, however each time I attempt this question I get an answer that makes absolutely no sense.

So, please help me,

Thank you! :)